normal cdf
Assuming "normal" is a probability distribution | Use as instead | Use "normal cdf" as

Input

cumulative distribution function | normal distribution | mean | μ standard deviation | σ (positive)

Result

1/2 erfc((μ - x)/(sqrt(2) σ))≈0.5 erfc((0.707107 (μ - x))/σ)

Alternate form

1/2 erfc(-(x - μ)/(sqrt(2) σ))
1/2 (1 - erf((μ - x)/(sqrt(2) σ)))
POWERED BY THE WOLFRAM LANGUAGE