1/6 (a^4 - 2 a^2 (3 b + 4) + 16 a b + 3 b^2)=b+2(b-a) integer solution1/6 (a^4 - 2 a^2 (3 b + 4) + 16 a b + 3 b^2)=b+2(b-a) integer solution

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