∫1/(e^t + e^(-t))dt

Indefinite integral

integral1/(e^t + e^(-t)) dt = tan^(-1)(e^t) + constant

Alternate form of the integral

1/2 i log(1 - i e^t) - 1/2 i log(1 + i e^t) + constant

Series expansion of the integral at t=0

π/4 + t/2 - t^3/12 + t^5/48 + O(t^6)
(Taylor series)