\int\limits_0^2 \sqrt{x^2+4x^4}dx

Definite integral

integral_0^2 sqrt(x^2 + 4 x^4)dx = 1/12 (17 sqrt(17) - 1)≈5.7577

Indefinite integral

integral sqrt(x^2 + 4 x^4)dx = ((4 x^2 + 1) sqrt(4 x^4 + x^2))/(12 x) + constant
POWERED BY THE WOLFRAM LANGUAGE